Assume that body temperatures of healthy adults are normally distributed with a mean of 98.20 F and a standard deviation of 0.62F - based on data from The Ohio State University researchers.

a) if you have a body temperature of 99.00F, what is your percentile score?
b) Convert 99.00F to a standard score (or z score)
c) Is a body temperature of 99.00F "unusual"? Why or why not?
d) 50 adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98F or lower?
e) A person's body temperature is found to be 101.00F. Is this result "unusual"? Why or why not? What should you conclude?
f) What body temperature is the 95th percentile?
g) What body temperature is the 5th percentile?
h) OSU hospital uses 100.6F as the lowest temperature to indicate fever. What percentage of normal and healthy adults would be considered to have a fever? Does this percentage suggest that a cutoff of 100.6F is appropriate?
i) If, instead of assuming that the mean body temperature is 98.20F, we assume that the mean is 98.60F (as many people believe) what is the chance of randomly selecting 106 people and getting a mean of 98.20F or lower? (continue to assume that the standard deviation is 0.62F.) OSU researchers did get such a result. What should we conclude?

1. Which of the following statements are correct?
a. A normal distribution is any distribution that is not unusual.
b. The graph of a normal distribution is bell-shaped.
c. If a population has a normal distribution, the mean and the median are not equal.
d. The graph of a normal distribution is symmetric.
Using the 68-

Tthe mean for a special distribution is 100 and the standard deviation is 15. What is the estimated percentile for an individual who had a score of 90 on this scale?

Week 2 Problem Sets
2. a 9
b 31
c 119
4. 54-59
50-55
45-49
40-44
35-39
30-34
25-29
20-24
15-19
10-14
6. When we generate a large volume of data, we are unlikely to be able to make sense of it by looking at all the data. The largest amount o

Misery loves company. It is time for the PE (professional engineer's exam). The results of the national test were normally distributed around the mean score of 70. A score of 60 points was a passing score. Since I know someone the knows someone, I found out that my score was 80 and I rated in the 80 percentile (bottom of the top

For a normally distributed test with a mean of 100 and standard deviation of 20:
a) What score would be associated with the 80th percentile?
b) What would the inter-quartile range be for the test?
c) What would be the percentile rank of a score of 125?
Please give detailed notes explaining the steps required to answer ea

1. The following are marks obtained by a group of 40 students on an English examination:
42 88 37 75 98 93 73 62
96 80 52 76 66 54 73 69
83 62 53 79 69 56 81 75
52 65 49 80 67 59 88 80
44 71 7

1. A sample of 148 of our statistics students rated their level of admiration for Hilary Rodham Clinton on a scale of 1 to 7. The mean rating was 4.06 and the standard deviation was 1.70. (For this exercise, treat this sample as the entire population of interest).
a. use these data to demonstrate that the mean of the z distr

The weight for a group of 18 month-0ld girls are normally distributed with a mean of 24.4 pounds and a standard deviation of 2.6 pounds. Use the table to find the percentage of 18 month-old girls who weigh more than 27.8 pounds.
z-score1. 0.1, 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1
Percentile 53.98, 57.9,