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    Z-Scores, Percentile, and Normal Distributions

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    The diameters of oranges in a certain orchard are normally distributed with a mean of 5.26 inches and a standard deviation of 0.50 inches.

    a. What percentage of the oranges in this orchard have diameters less than 4.5 inches?
    b. What percentage of the oranges in this orchard is larger than 5.12 inches?
    c. A random sample of 100 oranges is gathered and the mean diameter obtained was 5.12. If another sample of 100 is taken, what is the probability that its sample mean will be greater than 5.12 inches?
    d. Why is the z-score used in answering (a), (b), and (c)?
    e. Why is the formula for z used in (c) different from that used in (a) and (b)?

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    Solution Preview

    The diameters of oranges in a certain orchard are normally distributed with a mean of 5.26 inches and a standard deviation of 0.50 inches.

    Here,  = 5.26 in and  = 0.50 in

    a. What percentage of the oranges in this orchard have diameters less than 4.5 inches?
    Z=
    P(X < 4.5) = P(Z < -1.52) = 0.064255 = 6.43%

    b. What ...

    Solution Summary

    Normal Distributions and Z-Scores are investigated. The solution is detailed and well presented. The response received a rating of "5/5" from the student who originally posted the question.

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