# Two Normal Distribution Papers

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4-67.

P( Z > Z0) = 0.85

P( 0 < Z < Z0) = 0.85-0.5 = 0.35

Z0 = -1.04

X = 2348 - 762*1.04 = 1555.52

P( |z| < Z0) = 0.8

2*P( 0 < Z < Z0 ) = 0.8

P( 0 < Z < Z0 ) = 0.4

Z0 = 1.28,-1.28

When z = 1.28, X = 2348 + 1.28*762 = 3323.36

When z = -1.28, X = 1372.64

The bounds are 1372.64 and 3323.36

4.68

P( |z| < Z0) = 0.75

2*P( 0 < Z < Z0 ) = 0.75

P( 0 < Z < Z0 ) = 0.375

Z0 = 1.15,-1.15

Z0 = 1.15 then upper bound will be 12.1+2.5*1.15 = 14.975

Z0 = -1.15 then lower bound will be ...

#### Solution Summary

The solution discusses the two normal distribution papers.

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