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    Two Normal Distribution Papers

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    4-67.
    P( Z > Z0) = 0.85
    P( 0 < Z < Z0) = 0.85-0.5 = 0.35
    Z0 = -1.04
    X = 2348 - 762*1.04 = 1555.52
    P( |z| < Z0) = 0.8
    2*P( 0 < Z < Z0 ) = 0.8
    P( 0 < Z < Z0 ) = 0.4
    Z0 = 1.28,-1.28
    When z = 1.28, X = 2348 + 1.28*762 = 3323.36
    When z = -1.28, X = 1372.64
    The bounds are 1372.64 and 3323.36
    4.68
    P( |z| < Z0) = 0.75
    2*P( 0 < Z < Z0 ) = 0.75
    P( 0 < Z < Z0 ) = 0.375
    Z0 = 1.15,-1.15
    Z0 = 1.15 then upper bound will be 12.1+2.5*1.15 = 14.975
    Z0 = -1.15 then lower bound will be ...

    Solution Summary

    The solution discusses the two normal distribution papers.

    $2.19

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