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expected value and variance of randoam variable

Please see the attached file "Q11.5.doc" for the problem statement.

suppose that w is normal and has expected value a and variance sigma^2. so the expected value of u = exp(w) is exp(a + 0.5sigma^2).
What is the variance of u: var(u)?


Solution Summary

The solution shows how to find out the variance of u, which is the exponential function of a normally distributed variable.