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Equations Rewritten

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Give a brief description of the variable and whether the scale of measurement is nominal, ordinal, interval, or ratio, and why.

The Measurement Principles
Nominal : People or objects with the same scale value are the same on some attribute. The values of the scale have no 'numeric' meaning in the way that you usually think about numbers.
Ordinal: People or objects with a higher scale value have more of some attribute. The intervals between adjacent scale values are indeterminate. Scale assignment is by the property of "greater than," "equal to," or "less than.
Interval: Intervals between adjacent scale values are equal with respect the attribute being measured. E.g., the difference between 8 and 9 is the same as the difference between 76 and 77.
Ratio: There is a rationale zero point for the scale. Ratios are equivalent, e.g., the ratio of 2 to 1 is the same as the ratio of 8 to 4.

Examples of the Measurement Scales
Nominal : Gender. Ethnicity. Marital Status.

Ordinal: Movie ratings (0, 1 or 2 thumbs up). U.S.D.A. quality of beef ratings (good, choice, prime). The rank order of anything.

Interval: WAIS intelligence score.

Ratio: Annual income in dollars. Length or distance in centimeters, inches, miles, etc.

Explain what it means to say that this variable is "normally distributed." Then, define probability value and explain how a probability value of .05 in this example is related to the normal curve.
A random variable X is called "normally distributed" if X follows a normal distribution with mean E(X)= and standard deviation . In other words, for any real number x, the probability that X is less than or equal to x is equal to

If =0 and =1, then we call this distribution the standard normal distribution, denoted by N(0,1). Its probability density function is . The normal curve y=f(x) looks like

The probability corresponds to the area of the left red region R.

The probability corresponds to the area of the right blue region R'.

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Solution Summary

The solution rewrites equations and looks at the density functions of a normal curve.

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  • BSc , Wuhan Univ. China
  • MA, Shandong Univ.
Recent Feedback
  • "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
  • "excellent work"
  • "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
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