Two Hypothesis Testing Problems
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Problem 1:
Classic Golf, Inc. manages five courses in the Jacksonville, Florida, area. The Director wishes to study the number of rounds of golf played per weekday at the five courses. He gathered the following sample information.
Day Rounds
Monday 124
Tuesday 74
Wednesday 104
Thursday 98
Friday 120
At the .05 significance level, is there a difference in the number of rounds played by day of the week?
Problem 2:
A group of department store buyers viewed a new line of dresses and gave their opinions of them. The results were:
Opinion Number of Buyers Opinion Number of Buyers
Outstanding 47 Good 39
Excellent 45 Fair 35
Very good 40 Undesirable 34
Because the largest number (47) indicated the new line is outstanding, the head designer thinks that this is a mandate to go into mass production of the dresses. The head sweeper (who somehow became involved in this) believes that there is not a clear mandate and claims that the opinions are evenly distributed among the six categories. He further states that the slight differences among the various counts are probably due to chance. Test the null hypothesis that there is no significant difference among the opinions of the buyers. Test at the .01 level of risk. Follow a formal approach; that is, state the null hypothesis, the alternate hypothesis, and so on.
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Solution Summary
Solution attaches a .doc file that performs hypothesis tests at the required levels of significance for these two given data tables.
Education
- BSc , Wuhan Univ. China
- MA, Shandong Univ.
Recent Feedback
- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
- "excellent work"
- "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
- "Thank you"
- "Thank you very much for your valuable time and assistance!"
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