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Null Hypothesis of M&M colors with ANOVA

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The weights (in grams) of four different colors of M&M candies are given below, along with the mean weight and variance of each color, and the variance of the sample means. Use a one-way ANOVA at the 0.025 significance level to test the null hypothesis that the different color M&M candies have the same mean weight.

Red Orange Yellow Brown

0.966 0.820 0.883 0.982
0.942 0.793 0.858 0.859
0.905 0.786 0.851 0.855
0.890 0.778 0.848 0.840
0.878 0.735 0.769 0.696

Sum: 4.581 3.912 4.209 4.232
# of values: 5 5 5 5
Mean: 0.916 0.782 0.842 0.846
Variance: 0.00135 0.00095 0.00185 0.01032

Variance of sample means: 0.002996

F= 3.9031, and the critical value is 4.1528, so there is NOT sufficient evidence to reject the claim.

F= 3.5557, and the critical value is 4.0768, so there is NOT sufficient evidence to reject the claim.

F= 4.1410, and the critical value is 4.1528, so there is NOT sufficient evidence to reject the claim.

F= 3.9031, and the critical value is 3.7294, so there is sufficient evidence to reject the claim.

F= 4.1410, and the critical value is 4.0768, so there is sufficient evidence to reject the claim.

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The solution examines the null hypothesis of M&M colors with ANOVA.

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Null Hypothesis - need answer now at 7:34 p.m EST
The weights (in grams) of four different colors of M&M candies are given below, along with the mean weight and variance of each color, and the variance of the sample means. Use a one-way ANOVA at the 0.025 significance level to test the null hypothesis that the different color M&M candies have the same mean weight.
Red Orange Yellow Brown
0.966 0.820 0.883 0.982
0.942 0.793 0.858 0.859
0.905 0.786 0.851 0.855
0.890 0.778 0.848 ...

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