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    Null Hypothesis of M&M colors with ANOVA

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    The weights (in grams) of four different colors of M&M candies are given below, along with the mean weight and variance of each color, and the variance of the sample means. Use a one-way ANOVA at the 0.025 significance level to test the null hypothesis that the different color M&M candies have the same mean weight.

    Red Orange Yellow Brown

    0.966 0.820 0.883 0.982
    0.942 0.793 0.858 0.859
    0.905 0.786 0.851 0.855
    0.890 0.778 0.848 0.840
    0.878 0.735 0.769 0.696

    Sum: 4.581 3.912 4.209 4.232
    # of values: 5 5 5 5
    Mean: 0.916 0.782 0.842 0.846
    Variance: 0.00135 0.00095 0.00185 0.01032

    Variance of sample means: 0.002996

    F= 3.9031, and the critical value is 4.1528, so there is NOT sufficient evidence to reject the claim.

    F= 3.5557, and the critical value is 4.0768, so there is NOT sufficient evidence to reject the claim.

    F= 4.1410, and the critical value is 4.1528, so there is NOT sufficient evidence to reject the claim.

    F= 3.9031, and the critical value is 3.7294, so there is sufficient evidence to reject the claim.

    F= 4.1410, and the critical value is 4.0768, so there is sufficient evidence to reject the claim.

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    https://brainmass.com/statistics/hypothesis-testing/null-hypothesis-246679

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    Null Hypothesis - need answer now at 7:34 p.m EST
    The weights (in grams) of four different colors of M&M candies are given below, along with the mean weight and variance of each color, and the variance of the sample means. Use a one-way ANOVA at the 0.025 significance level to test the null hypothesis that the different color M&M candies have the same mean weight.
    Red Orange Yellow Brown
    0.966 0.820 0.883 0.982
    0.942 0.793 0.858 0.859
    0.905 0.786 0.851 0.855
    0.890 0.778 0.848 ...

    Solution Summary

    The solution examines the null hypothesis of M&M colors with ANOVA.

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