Inferences Two Samples
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See attachment below. Please show how all work was obtained.
A) State the null and alternate hypothesis.
B) Determine the rejection region. For example "if , then reject ".
C) Determine the Test Statistic.
D) Conclude either "Reject " or "Do not reject " based on your analysis and answer the question.
E) Determine the p value of the test.
An educator believes that new reading activities in the classroom will help elementary school pupils improve their reading ability. She arranges for a third grade class of 11 students to follow these activities for an 8-week period. A control classroom of 13 third graders follows the same curriculum without the activities. At the end of the 8 weeks, all students are given the Degree of Reading Power (DRP) test, which measures the aspects of reading ability that the treatment is designed to improve. The table below represents the results of this test (assume the population Standard Deviations are equal). See Data Set for values below.
Based on the evidence provided, does it appear that these new reading activities actually improve scoring on the DRP at the 5% significance level?_________
Treatment 51 55 57 24 52 31 42 47 57 51 50
Control 39 29 61 42 35 62 47 44 71 49 42 40 45
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Solution Summary
The inferences of two samples are examined. The expert determines the test statistics for p value of the tests.
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See attachment #4 Question.doc please! Hope it helps.
A) State the null and alternate hypothesis.
B) Determine the rejection region. For example "if , then reject ".
C) Determine the Test Statistic.
D) Conclude either "Reject " or "Do not reject " based on your analysis and answer the question.
E) Determine the p value of the test.
An educator believes that new reading activities in the classroom will help elementary school pupils improve their reading ability. She arranges for a third grade class of 11 students to follow these ...
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- BSc , Wuhan Univ. China
- MA, Shandong Univ.
Recent Feedback
- "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
- "excellent work"
- "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
- "Thank you"
- "Thank you very much for your valuable time and assistance!"
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