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Hypothesis test for a mean of survey interviews

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Hugger Polls contends that an agent conducts a mean of 53 in-depth home surveys every week. A streamlined survey form has been introduced, and Hugger wants to evaluate its effectiveness. The number of in-depth surveys conducted during a week by a random sample of agents are:

53 57 50 55 58 54 60 52 59 62 60 60 51 59 56

At the .05 level of significance, can we conclude that the mean number of interviews conducted by the agents is more than 53 per week? Use a standard deviation of 3.7378. If you use Excel or Megastat, embed the spreadsheet/worksheet into this exercise.

a. Set up the null hypothesis and alternative hypothesis.

b. State the decision rule.

c. Show calculations for the test statistic.

d. What is your decision?

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Solution Summary

The solution gives step-by-step instructions for conducting a hypothesis test for a mean using a one-sample t test. The solution contains the null and alternative hypotheses, the decision rule we will use to come up with an answer, calculations for the test statistics, and conclusions of our findings.

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