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    Hypothesis Testing: Compute the statistical z test and deciding what to do with the null.

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    In a recent national survey, the mean weekly allowance for a nine-year-old child from his/her parents was reported to be $3.65. A random sample of 45 nine-year-olds in northwestern Ohio revealed the mean allowance to be $3.69 with a standard deviation of 0.24. At the 0.05 level of significance is there a difference in the mean allowances nationally and the mean allowances in northwestern Ohio for nine-year-olds.
    Test = z test
    State the research hypothesis and the Null hypothesis.

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    Solution Preview

    Let the mean allowances in northwestern Ohio be U.
    <br>H0: U=3.65 (there's no difference)
    <br>H1: U<>3.65(there is a significant difference)
    <br>We can use z ...

    Solution Summary

    The solution addresses a recent national survey, the mean weekly allowance for a nine-year-old child from his/her parents was reported to be $3.65. A random sample of 45 nine-year-olds in northwestern Ohio revealed the mean allowance to be $3.69 with a standard deviation of 0.24. At the 0.05 level of significance is there a difference in the mean allowances nationally and the mean allowances in northwestern Ohio for nine-year-olds.
    Test = z test
    State the research hypothesis and the Null hypothesis.

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