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Hypothesis Testing: Compute the statistical z test and deciding what to do with the null.

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In a recent national survey, the mean weekly allowance for a nine-year-old child from his/her parents was reported to be \$3.65. A random sample of 45 nine-year-olds in northwestern Ohio revealed the mean allowance to be \$3.69 with a standard deviation of 0.24. At the 0.05 level of significance is there a difference in the mean allowances nationally and the mean allowances in northwestern Ohio for nine-year-olds.
Test = z test
State the research hypothesis and the Null hypothesis.

https://brainmass.com/statistics/hypothesis-testing/4510

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Let the mean allowances in northwestern Ohio be U.
<br>H0: U=3.65 (there's no difference)
<br>H1: U<>3.65(there is a significant difference)
<br>We can use z ...

Solution Summary

The solution addresses a recent national survey, the mean weekly allowance for a nine-year-old child from his/her parents was reported to be \$3.65. A random sample of 45 nine-year-olds in northwestern Ohio revealed the mean allowance to be \$3.69 with a standard deviation of 0.24. At the 0.05 level of significance is there a difference in the mean allowances nationally and the mean allowances in northwestern Ohio for nine-year-olds.
Test = z test
State the research hypothesis and the Null hypothesis.

\$2.49