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# Comparing Means

Restaurateur Danny Valentine is evaluating two, sites, Raymondville and Rosenber, for his next restaurant. Denny suspects that Raymondville residents (population 1) dine out more often (number of times per month) than Rosenberg residents (population 2).

Denny commissions a market survey to test his hypothesis. The market researcher used a random sample of 64 families from each suburb and recorded the number of times each population dines out.

The market researcher finds that the sample difference in the mean number of dine out times is 3.54 population1 - population 2. The calculated two-tail p-value =.03. Assuming alpha=.02

Should the hypothesis null hypothesis be rejected or accepted, or the alternate hypothesis?

#### Solution Preview

In this problem, you are comparing the mean number of times residents dine out in two cities. You would do this using a two-sample t-test.

It's not clear whether this should be a one-tailed or two-tailed test. The fact that Denny suspects that Raymondville residents dine out more often than Rosenberg residents suggests a one-tailed test. The fact that you are given the two-tailed p-value suggests a two-tailed test. I suspect that your teacher wants you to read problem closely enough to see that Denny should do a one-tailed test. ...

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