Explore BrainMass

Bellevue Steel: value of test statistic, decision rule etc

Part 4

The production manager at Bellevue Steel, a manufacturer of wheelchairs, wants to compare the number of defective wheelchairs produced on the day shift with the number on the afternoon shift. A sample of the production from 6 day shifts and 8 afternoon shifts revealed the following number of defects. Assume this is a two sample "Unknown Variances, Assumed Equal". The level of significance is 0.05. The standard deviation for Day is 1.4142 and the standard deviation for Afternoon is 2.2678.

Day 5 8 7 6 9 7
Afternoon 8 10 7 11 9 12 14 9

1. Set up the null and alternative hypothesis.

2. Calculate the value of the test statistic.
Note: if you use manual or Megastat, select Hypothesis Test: Independent Groups (t test, pooled variance)

What is the value of the test statistic?

3. What is the decision rule (DR)?

Reject Ho if (complete the DR in next box)

4. What is your decision regarding Ho?

Accept or Reject Ho?

Solution Summary

A Complete, Neat and Step-by-step Solution is provided in the attached Excel file.