The production manager at Bellevue Steel, a manufacturer of wheelchairs, wants to perform a second analysis of the number of defective wheelchairs produced on the day shift and afternoon shift. A sample of the production from 6 day shifts and 8 afternoon shifts revealed the following number of defects.
At the 0.05 significance level, is there a difference in the mean number of defects per shift?
Day 10 9 6 6 8 9
Afternoon 8 10 7 5 4 10 5 6
1. State the null and alternate hypotheses.
2. What is the decision rule?
3. What is the value of the test statistic?
4. What is your decision regarding the null hypothesis?
5. What is the p-value?
6. Interpret the result.
The solution provides step-by-step method of performing a 5 step hypothesis test. All the steps of hypothesis testing (formulation of null and alternate hypotheses, selection of significance level, choosing the appropriate test-statistic, decision rule, calculation of test-statistic and conclusion) have been explained and the statistical analysis has been shown in details. This solution is provided in an attached Excel file and a Word file with a PDF copy.