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# Earl Babbie exercise using the mean and range using bivarate tables

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Using the MEAN & RANGE to describe the distribution of responses to the question, "How often have you used the library as a place to study.." FOR ALL RESPONDENTS.

Next CONSTRUCT 2 BIVARIATE TABLES. Each should be TITLED, PERCENTAGE, & INCLUDE THE NUMBER OF CASES ON WHICH THE PERCENTAGES ARE BASED. Be sure to PLACE YOUR IV IN THE COLUMNS & YOUR DV IN THE ROWS**. INTERPRET THE RESULTS*.

VARIABLES:
Are you Female or Male? 1 Yes 2 NO.
How often have you used the library as a place to study during the last semester?

FREQUENCIES TABLE 1
GRAD 1 not at all 243 UNDERGRAD 1 not at all 105

FREQUENCIES TABLE 2
Male 1 not at all 58 Female 1 not at all 290
Male 2 1 -3 times 33 Female 2 1 -3 times 140
Male 3 Monthly 21 Female 3 Monthly 72
Male 4 Weekly 28 female 4 Weekly 77.

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This solution explains Earl Babbie exercise using the mean and range using bivarate tables.

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Earl Babbie exercise using the MEAN and RANGE using BIVARIATE TABLES
Using the MEAN & RANGE to describe the distribution of responses to the question, "How often have you used the library as a place to study.." FOR ALL RESPONDENTS.
Analysis. We assume that there are 4 months and 16 weeks in one semester.
There are FOUR groups of RESPONDENTS: graduate students; undergraduate students; males and females. For each of their distribution of responses, the mean and range are
There are 243+87+24+15=369 graduate students in total. So,
Mean=
Range=maximum-minimum=16-0=16
There are 105+89+69+92=355 undergraduate students in total. So,
Mean=
Range= maximum-minimum=16-0=16.
c) males.
There are 58+33+21+28=140 males in total. So,
Mean=
Range= maximum-minimum=16-0=16.
d) females.
There are 290+140+72+77=579 females in total. So,
Mean=
Range= maximum-minimum=16-0=16.

Next CONSTRUCT 2 BIVARATE TABLES. Each should be TITLED, PERCENTAGE, & INCLUDE THE NUMBER OF CASES ON WHICH THE PERCENTAGES ARE ...

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• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
• "Thank you"
• "Thank you very much for your valuable time and assistance!"

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