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# Probability and Standard Deviation Determination

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please explain how to solve for probability...
If i have a class of 14 males and 36 females and the professor selects a name from the class using random sampling what is the probability that the first student selected will be a female?
P=

If the random sample of n=3 students is selected and the first two are both females what is the probability that the third student selected will be a male?
p=

If i have a mean = 0
standard deviation =1

z= -2.25 and z= +2.25
p=____

z= -2.50 and z = +2.50
p=_____

z= - 0.70 and z= +0.70

How do i set this problem up to solve?

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https://brainmass.com/statistics/data-collection/probability-and-standard-deviation-determination-583998

#### Solution Preview

1. P(female)=36/(14+36)=0.72

2. Since we select 3 students, first two are females. ...

#### Solution Summary

The solution gives detailed steps on computing probability using random sampling and using standard normal distribution.

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## Probability of Proportions

A given population proportion is .25. For the given value of n, what is the probability of getting each of the following sample proportions?

a. n = 110 and p̂ ≤ .21

b. n = 33 and p̂ > .24

c. n = 59 and .24 ≤ p̂ < .27

d. n = 80 and p̂ < .30

e. n = 800 and p̂ < .30

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