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# Spearman's correlation coefficient

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Hello,

I need to find out the Spearman's correlation coefficient of the attached data, I have analysed it using an Excel macro and come up with a different result from when I worked it out manually, using forumlas I found on the web.

I'm having trouble deciding which method is the right one, so I'd like someone to take my data and work out the correlation coefficient with the method they know to be correct (like I do not!).

The p value is .05 (1-tailed)

I am not very confident with statistics so if you could provide an easy-to-understand explanation to the figures and the steps used to get them it would be greatly appreciated!

I also need to know if the result is statistically significant.

##### Solution Summary

Using Spearman's correlation coefficient, I'd like someone to take my data and work out the correlation coefficient with the method they know to be correct (like I do not!).

The p value is .05 (1-tailed)

Child Test A Results Test B Results
1 7 18
2 4 9
3 4 6
4 3 24
5 4 14
6 7 39
7 12 20
8 5 18
9 4 13
10 4 10

##### Solution Preview

Hello,

I need to find out the Spearman's correlation coefficient of the attached data, I have analysed it using an Excel macro and come up with a different result from when I worked it out manually, using forumlas I found on the web.

I'm having trouble deciding which method is the right one, so I'd like someone to take my data and work out the correlation coefficient with the method they know to be correct (like I do not!).

The p value is .05 (1-tailed)

I am not very confident ...

Solution provided by:
###### Education
• BSc , Wuhan Univ. China
• MA, Shandong Univ.
###### Recent Feedback
• "Your solution, looks excellent. I recognize things from previous chapters. I have seen the standard deviation formula you used to get 5.154. I do understand the Central Limit Theorem needs the sample size (n) to be greater than 30, we have 100. I do understand the sample mean(s) of the population will follow a normal distribution, and that CLT states the sample mean of population is the population (mean), we have 143.74. But when and WHY do we use the standard deviation formula where you got 5.154. WHEN & Why use standard deviation of the sample mean. I don't understand, why don't we simply use the "100" I understand that standard deviation is the square root of variance. I do understand that the variance is the square of the differences of each sample data value minus the mean. But somehow, why not use 100, why use standard deviation of sample mean? Please help explain."
• "excellent work"
• "Thank you so much for all of your help!!! I will be posting another assignment. Please let me know (once posted), if the credits I'm offering is enough or you ! Thanks again!"
• "Thank you"
• "Thank you very much for your valuable time and assistance!"

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