Explore BrainMass

# Confidence Interval

Not what you're looking for? Search our solutions OR ask your own Custom question.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

Please provide step by step instructions using actual numbers instead of formulas for solving the following 3 problems, thanks

3. Determine whether the average number of calories in a homemade cookie is more than a store-bought one. Estimate the difference in the mean calories between the two types using a 90% confidence interval.
storebought n=45 x-bar=179 s=4

4. A childcare agency was interestin in examining the amount that families pay per child per month for childcare outside the home. A randome sample of 64 families was selected and the mean and the standard deviation were computed to be \$675 and \$80 respectively.
a. Find a 95% confidence interval for the true average amount spent per child per month for childcare outside the home.
b. Interpret the interval found in part a.
c. A social worker claims that the average amount spent per child per month outside the home is \$700. Based on the interval in part a can this claim be rejected?
d. Find a 95% upper confidence bound for the true average amount spent per child per month on childcare outside the home.

https://brainmass.com/statistics/confidence-interval/statistics-confidence-interval-7087

#### Solution Preview

3. Solution. Xbar=180, sx=2,n1=40, Ybar=179, sy=4, n2=45, 1-alpha=0.1, so a=alpha/2=0.05
t_0.05(n1+n2-2)=1.658.
therefore, we get the confidence interval of the difference in the mean of two types as ...

#### Solution Summary

The expert determines whether the average number of calories in a homemade cookie is more than a store-bought one. The difference in the mean calories between the two types using a 90% confidence interval is estimated.

\$2.49