A supervisor for a large company wishes to estimate the proportion of parts from a supplier that are defective. He has selected a random sample of n = 200 incoming parts and has found 11 to be defective. Based on a 95% confidence level, the upper and lower limits for the confidence interval estimate are approximately 0.0234 to 0.0866
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p = 11/200 = 0.055, q = 1 - p = 0.945
Standard error, SE = ...
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