A random sample of size of 25 taken from a normally distributed population yielded a sample variance of 2.25. What is the value for the maximum error of estimate for a 90% confidence interval for the population mean?© BrainMass Inc. brainmass.com October 4, 2022, 12:08 pm ad1c9bdddf
SOLUTION This solution is FREE courtesy of BrainMass!
n = 25, s = sqrt(variance) = sqrt(2.25) = 1.5, z- score for 90% confidence = 1.645
Margin of error, E = z * (s/sqrt n) = 1.645 * (1.5/sqrt 25) = 0.4935
The maximum error of estimate is 0.4935.© BrainMass Inc. brainmass.com October 4, 2022, 12:08 pm ad1c9bdddf>