# Hypothesis Testing & Confidence Interval: Mean sleep

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See data file attached.

Compare the mean of the "Sleep" data to the national average of 6.9, with a standard deviation of 1.38.

Perform the following statistical operations using a Microsoft Word document:

State a research (directional) hypothesis and the null hypothesis about the populations

Determine the cutoff sample score at a significance level of 5%

Calculate the standard error of the mean

Calculate a zobt score

Compare the zobt to the zcrit

Calculate a confidence interval or explain why a confidence interval adds no information to the results

Interpret and report on your findings (in English and statistical notation)

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##### Solution Summary

The solution provides step by step method for the calculation of testing of hypothesis and confidence interval. Formula for the calculation and Interpretations of the results are also included. Interactive excel sheet is included. The user can edit the inputs and obtain the complete results for a new set of data.

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Please see the attachments.

Using the data in the attached document, I need to compare the mean of the "Sleep" data in it to the national average of 6.9, with a standard deviation of 1.38.

Perform the following statistical operations using a Microsoft Word document:

State a research (directional) hypothesis and the null hypothesis about the populations

The null hypothesis tested is

H0: Mean sleep ≥ 6.9. (µ ≥ 6.9)

The alternative hypothesis is

H1: Mean sleep < 6.9. (µ < 6.9)

Determine the cut-off sample score at a significance level of 5%

Cut-off sample score can be obtained from the standard normal table at the ...

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