a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. What, if any assumption did you make about the distribution of proportional limit stress?
b) Calculate and interpret a 95% lower prediction bound for the proportional limit stress of a single joint of this type.
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See the attached file.
Sample mean =8.48 MPa
Standard deviation s= 0.79 MPa
Significance level (alpha (a) ) corresponding to 95% confidence = 100%-95% =5% or 0.05
Degrees of freedom (df) for sample size , n= 14 is (n-1) or 14-1=13
t -critical (0.05, 13) = 1.771
The t critical value is obtained from t-distribution table with df = (n - ...
The solution calculates the lower bound of confidence interval.