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    Normal probability and Chi square test.

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    For df = 5 and the constant A, identify the value of A such that

    a. P (x2 > A) = 0.90
    b. P (x2 > A) = 0.10
    c. P (x2 > A) = 0.95
    d. P (x2 > A) = 0.05
    e. P (x2 < A) = 0.0975
    f. P(x2 < A) = 0.025

    2. It has been reported that 10.3% of US households do not own a vehicle, with 34.2% owning 1 vehicle, vehicles. The data for a random sample of 100 households in a resort community are summarized in the frequency distribution below. At the 0.05 level significance, can we reject the possibility that the vehicle-ownership nation as a whole?

    Number of Number of
    Vehicles Owned Households

    0 20
    1 35
    2 23
    3 or more 22
    -----
    100

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    https://brainmass.com/statistics/chi-squared-test/normal-probability-and-chi-square-test-221144

    Solution Summary

    The solution provides step by step method for the calculation of probability and chi square test . Formula for the calculation and Interpretations of the results are also included.

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