Normal probability and Chi square test.
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For df = 5 and the constant A, identify the value of A such that
a. P (x2 > A) = 0.90
b. P (x2 > A) = 0.10
c. P (x2 > A) = 0.95
d. P (x2 > A) = 0.05
e. P (x2 < A) = 0.0975
f. P(x2 < A) = 0.025
2. It has been reported that 10.3% of US households do not own a vehicle, with 34.2% owning 1 vehicle, vehicles. The data for a random sample of 100 households in a resort community are summarized in the frequency distribution below. At the 0.05 level significance, can we reject the possibility that the vehicle-ownership nation as a whole?
Number of Number of
Vehicles Owned Households
0 20
1 35
2 23
3 or more 22
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100
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Solution Summary
The solution provides step by step method for the calculation of probability and chi square test . Formula for the calculation and Interpretations of the results are also included.
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