# Normal probability and Chi square test.

For df = 5 and the constant A, identify the value of A such that

a. P (x2 > A) = 0.90

b. P (x2 > A) = 0.10

c. P (x2 > A) = 0.95

d. P (x2 > A) = 0.05

e. P (x2 < A) = 0.0975

f. P(x2 < A) = 0.025

2. It has been reported that 10.3% of US households do not own a vehicle, with 34.2% owning 1 vehicle, vehicles. The data for a random sample of 100 households in a resort community are summarized in the frequency distribution below. At the 0.05 level significance, can we reject the possibility that the vehicle-ownership nation as a whole?

Number of Number of

Vehicles Owned Households

0 20

1 35

2 23

3 or more 22

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100

https://brainmass.com/statistics/chi-squared-test/normal-probability-and-chi-square-test-221144

#### Solution Summary

The solution provides step by step method for the calculation of probability and chi square test . Formula for the calculation and Interpretations of the results are also included.