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    Chi square goodness of fit test

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    Research has demonstrated that people tend to be attracted to others who are similar to themselves. One study demonstrated that individuals are disproportionately more likely to marry those with surnames that begin with the same last letter as their own. The researchers began by looking at marriage records and recording the surname for each groom and the maiden name of each bride. From these records it is possible to calculate the probability of randomly matching a bride and groom whose last names begin with the same letter. Suppose that this probability is only 6.5%. Next , a sample of n=200 married couples is selected and the number who shared the same last initial at the time they were married is counted. The resulting observed frequencies are as follows: Same initial 19 Different initials 181 Total 200. Do these date indicate that the number of couples with the same last initial is significantly different that would be expected if couples were matched randomly? Test with a= .05.

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    This solution is an example of a chi square goodness of fit test with only two categories. A table of observed and expected counts is included along with a 236 word explanation and interpretationn of the test.