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Chi-square goodness of fit analysis

An EMT Service keeps records of emergency calls. A study of 150 five-minute time intervals resulted in the distribution of number of calls as follows. For example, during 18 of the five-minute intervals, no calls occurred. USe the chi-sqaure goodness-of-fit test and significance level =.01 to determine whether this distribution is Poisson. Analyze the results and interpret what they mean in relation to the problem. Use the 5-step hypothesis testing procedure:

Number of calls(per 5-minute interval) - Frequency
0 - 18
1 - 28
2 - 47
3 - 21
4 - 16
5 - 11
6 or more - 9

A-What are the null and alternative hypothesis?
B-What is the critical value for sample test statistics if the test of hypothesis to be evaluated at 1% significance?
C-What is the value of the sample test statistic?
D-Based on the value of test statistic and its critical value, what statement should be made about the null hypothesis?
E-What is the conclusion based on the statement made about null hypothesis in part D?

Solution Summary

This solution involves applying statistical concepts such as null and alternative hypotheses and critical values.