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Chi square test for goodness of fit

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19. In a particular market there are three commercial television stations, each with its own evening news program from 6:00 to 6:30 P.M. According to a report in this morning's local newspaper, a random sample of 150 viewers last night revealed 53 watched the news on WNAE (channel 5), 64 watched on WRRN (channel 11), and 33 on WSPD (channel13). At the .05 significance level, is there a difference in the proportion of viewers watching the three channels?

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Solution Summary

Step by step method for testing the chi square goodness of fit hypothesis under 5 step approach is discussed here. Excel template for each problem is also included. This template can be used to obtain the answers of similar problems.

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