An archer pulls the bowstring back for a distance of 0.470 m before releasing the arrow. The bow and string act like a spring whose spring constant is 425 N/m.
(a) What is the elastic potential energy of the drawn bow?
(b) The arrow has a mass of 0.0300 kg. How fast is it traveling when it leaves the bow?
The elastic potential energy of the drawn bow = 0.5 * (425 N / m) * (0.470 m) ^ 2 = 46.9 ...
This solution calculates the potential energy of a drawn bow and the speed with which the arrow leaves the bow.