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Work Required to Stretch a Spring; Elastic Potential Energy

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Explain why the work required to stretch a spring or other elastic object with a linear restoring force, of form F = - kx, from its equilibrium position to displacement x is `dW = .5 k x^2, and why we hence say that this is the elastic potential energy of the object in this position.

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The solution discusses how work required to stretch a spring and elastic potential energy.

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