Let the distances measured along the wedge ar denoted by x and the perpendicular distance of point B from the wedge is y:
y = 4*sin(15) = 1.035276 ft
xo(initial x) = 4*cos(15)= 3.8637 ft
Since a 30 lb force is applied vertically downward on the hanging pulley (massless), therefore, tension (T) on each side of the pulley will be 15 lb (no friction).

Now for block A:
At any ...

Solution Summary

The solution answers what happens to a block that goes up an incline, particularly with respect to its velocity.

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... Net force on the block down the incline = F = mgsin15O f ... A and B just after impact/Relative velocity of A ... 1 sinθ) where vA and vB are velocities of A ...

... is the initial velocity, v is the final velocity, a is ... 4: A block is at rest on an inclined plane whose ... m Net force on the block down the incline = mgsinθ - f ...

... positive x direction and some time later has a velocity of 6.0 ... c) What is the speed of the block just before ... the skier moved a distance of 8.0m up the incline. ...

... b. Find the velocities of the stone and the ball ... the magnitude and direction of the stone's velocity just before ... Where does the ski jumper land on the incline? ...