Question: The artery is 2/3 blocked. The normal speed is 0.40 m/s and blood density is 1060 kg/m^3. Find the velocity of the blood at the blocked area. Find the pressure difference between the normal and blocked area.

Solution Preview

To calculate the velocity: A1 v1 = A2 v2

In this case, A2 = (2/3) A1,

A1 v1 = (2/3) A1 v2
0.40 m/s ...

Solution Summary

This solution is comprised of a step by step response which addresses both variables in this problem which need to be solved for. The equations required for solving this problem are provided in the solution and each part of this problem is worked through, showing the accompanying algebra.

... just out side the hole is atmospheric pressure) hH= Height of the hole = H - h1 vH = Velocity of the ... H-h1)ρg + ½ ρ(vH)2 ____ _____ Solving we get ...

... a) Solve for 't' Answer: Show your work here: b) Find 't ... v=12.1sqrt(p) Where v is the velocity in feet per second and p is the nozzle pressure, in pounds ...

... b) Calculate the pressure in the smaller section in units of Pa. ... SOLUTION Basic theory. ... If the velocity of the liquid at any cross section is v, the liquid will ...

...Solving we get : t = 40 deg.C. ... Power = Force x Displacement/Time = Force x Velocity. ... 300 K Pressure = Atmospheric pressure = 1.013 x 105 Pa Increase in temp. ...

... k is a constant that is determined by the pressure, viscosity of ... c. What distance r would give a velocity of 0 cm ... x^2 + 99.970x - 4454.10 = 0 On solving, we get ...

... kg-1 and density of 1.7 kg ms-3. The steam leaves the turbine with a velocity of 30 m ... of 2900 kJ kg-1, density of 0.7 kg m-3 and at a pressure of 1.2 ... Solution: ...

... water, av = constant where a = area of cross section at any section of the stream and v = velocity of water ... Solution: Pressure outside = 1 atm = 1.013 x 105 Pa. ...

... transported across the city with wind velocity of 8 ... not exceed 10 decibels, the sound pressure of concern ... provides step by step methodology to solve the given ...