Question: The artery is 2/3 blocked. The normal speed is 0.40 m/s and blood density is 1060 kg/m^3. Find the velocity of the blood at the blocked area. Find the pressure difference between the normal and blocked area.
To calculate the velocity: A1 v1 = A2 v2
In this case, A2 = (2/3) A1,
A1 v1 = (2/3) A1 v2
0.40 m/s ...
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