Question: The artery is 2/3 blocked. The normal speed is 0.40 m/s and blood density is 1060 kg/m^3. Find the velocity of the blood at the blocked area. Find the pressure difference between the normal and blocked area.

Solution Preview

To calculate the velocity: A1 v1 = A2 v2

In this case, A2 = (2/3) A1,

A1 v1 = (2/3) A1 v2
0.40 m/s ...

Solution Summary

This solution is comprised of a step by step response which addresses both variables in this problem which need to be solved for. The equations required for solving this problem are provided in the solution and each part of this problem is worked through, showing the accompanying algebra.

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