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    Physics - Motion

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    A .51kg object is at rest. a 2.70 N force to the right acts on the object during a time interval of 1.32s
    A) what is the velocity of the object at the end of this time interval? (in m/s)
    B) at the end of this interval, a constant force of 3.86N to the left is applied for 3.02s
    What is the velocity at the end of the 3.02s? (in m/s)

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    Solution Preview

    m = 0.51 kg, F = 2.7 N, t = 1.32 s.

    Impulse = force x time = 2.7 x 1.32 = 3.564 ...

    Solution Summary

    The expert examines the motion and velocity of objects. Complete, neat and step-by-step solutions are provided.