A dockworker applies a constant horizontal force of 80.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 m in 5.00 s.
a) What is the mass of the block of ice?
b) If the worker stops pushing at the end of 5.00 s, how far does the block move in the next 5.00 s
Please find the answer to your question below.
Force = 80 N
Distance , s = 11 m
Time , t = 5 sec
Now , initial velocity , u = 0
final velocity , v = ?
Using , s = ut + 0.5 a t^2
11 = 0*5 + 0.5 * a * 5^2
which gives a = 22 / 25 ...
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