Purchase Solution

Momentum of a Broken Spaceship Piece After Explosion

Not what you're looking for?

Ask Custom Question

A spaceship of mass 2.3*10^6 kg is cruising at a speed of 4.4*10^6 m/s when the antimatter reactor fails, blowing the ship into three pieces. One section, having a mass of 5.1*10^5 kg, is blown straight backward with a speed of 2.1*10^6 m/s. A second piece, with mass 7.6*10^5 kg, continues forward at 1.1*10^6 m/s. What is the speed of the third piece in m/s?

Purchase this Solution
Solution Summary

The solution draws an equation from the relevant theory and plugs in the given speeds of the two other spaceship debris pieces to find the velocity of the last part of the spaceship after engine trouble led to it being blown into three pieces.

Solution Preview

mass of spaceship M = 2.3*10^6 kg
velocity of spaceship V = 4.4*10^6 m/s

After a blow-up,
m1 = ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
Recent Feedback
  • " In question 2, you incorrectly add in the $3.00 dividend that was just paid to determine the value of the stock price using the dividend discount model. In question 4 response, it should have also been recognized that dividend discount models are not useful if any of the parameters used in the model are inaccurate. "
  • "feedback: fail to recognize the operating cash flow will not begin until the end of year 3."
  • "Answer was correct"
  • "Great thanks"
  • "Perfect solution..thank you"
Purchase this Solution
Free BrainMass Quizzes
Introduction to Nanotechnology/Nanomaterials

This quiz is for any area of science. Test yourself to see what knowledge of nanotechnology you have. This content will also make you familiar with basic concepts of nanotechnology.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Basic Physics

This quiz will test your knowledge about basic Physics.

The Moon

Test your knowledge of moon phases and movement.

View More Free Quizzes
Related BrainMass Solutions

  • Ignoring and Including Special Relativity

    of momentum ; Momentum of spaceship after explosion = 0 So m1 v1 +m2 v2 = 0 Where m1 and m2 are mass of the two fragments and v1 and v2 are the velocities of the two fragments.

  • Friction force, impulse momentum, mass and speed, direction

    (1) Applying the principle of conservation of linear momentum: Momentum of Laura after jump + Momentum of canoe after jump = Momentum of Laura before jump + Momentum of canoe before jump 35 x VLW + 55 x VCW = 0 .........(2) (assuming the canoe

  • Calculations on an Exploding Projectiles

    Now we can use the law of conservation of momentum to determine the velocity of the large particle after the explosion.

  • Examination of the affect of an explosion on motion of carts

    Making the Measurements Mark the starting position of the cart with a piece of masking tape on the table top. With another piece of masking tape, mark the position the cart reaches after the explosion.

  • impulse and momentum

    After the explosion, a 0.20-kg piece moves south at 4 m/s. What are the components of the velocity of the 0.30-kg piece? Question #4 Two cars of equal mass collide on a horizontal frictionless surface.

  • Problems on relativity

    new spaceship that can travel at a speed of 0.920c.

  • Block Problems

    (velocity of 1st piece after explosion) Hence, v1 = sqrt(2*mu1*g*s1) => v1 = sqrt(2*0.40*9.8*0.15) =1.084 m/s Similarlly, for 2nd piece, v2 = sqrt(2*mu2*g*s2) m2 = ?

  • Velocity of fragments after an explosion

    One fragment move upward with a speed of 450 m/s following the explosion. The Second fragment has a speed of 300 m/s and is moving east right after the explosion. provide all work.

  • Using the Law of Conservation of Momentum

    Provides a solution using the law of conservation of momentum.

View More Related Solutions