I'm completely lost - Could you go step by step so I can follow your logic? Thanks.

1. A crate sits on a flatbed truck. This truck, initially travelling at a velocity of 80 km/hour, comes to a stop in 22 meters. What is the minimum coefficient of static friction required between the crate and truck bed, if it is not to slide forward?

2. A hospital traction device is shown in (attached). What is a) the horizontal force and b) the vertical force exerted on the foot by the arrangement, if the cord transmits an undiminished tension T of 5.0 gN?

1) Recall that acceleration is the change in velocity over change in time.

Look at the units: v = 80 km/hr = 80,000 m/hr = 22 m/s (initial velocity)

Use the following equation to find the acceleration: v^2 = (vo)^2 + 2a(x-xo), where v^2 is velocity squared, (vo)^2 is initial velocity squared, a is acceleration, x is position, and xo is the ...

Solution Summary

The answers are determined by looking at the relationships between velocity and acceleration and frictional force. The minimum coefficient of friction and the horizontal/vertical forces are calculated by using all these parameters and the variable of time.

A 17.2 kg box is released on a 38.1 degree incline and accelerates down the incline at 0.269 m/s^2. Find the friction force impeding its motion, and the coefficient of friction.

1.) A horizontal force of 3.00 N is applied to a 1.00-kg radio, initially at rest on a table with a level surface.
a.) Will the radio move if the coefficient of the friction is 0.45?
b.) What is the coefficient of friction if it just begins to move?
c.) What is its acceleration if the coefficient of the friction is only 0.0

A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.190 and the push imparts an initial speed of 4.20 m/s?

If an object slides directly down an inclined place, at a constant velocity of 6 m/s, how large is the coefficient of kinetic friction if the plane make an angle of 25 degrees with the horizontal?

It's not a problem but I need a good explanation please because I really don't understand:
I need someone to explain why when we have (for example) one block on another, why when we represent the friction force, its direction can sometimes become, in the same sense, not only direction but also acceleration? How is this possib

Find the force P necessary to push a 50.6 kg block down an incline of 32.4 degrees with an acceleration of 1.78 m/s^2. P is parallel to the incline and the coefficient of friction between the block and the incline surface is 0.805.
Picture is attached.

Question: A 16-kg sled is being pulled along the horizontal snow-covered ground by a force of 24 N. Starting from rest, the sled attains a speed of 2.0 m/s in 8.0 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.

A skier is moving at 20.0 m/s down a 30 degree slope. He encounters wet snow and slides 145 meters before coming to a stop. What is the coefficient of friction between the skis and the snow?

Does kinetic friction depend on area? What about Normal force? or speed? And what is the difference between static and kinetic friction.
Please help me understand kinetic friction.

To measure the static friction coefficient between a 1.9 kg block and a vertical wall, the setup shown in the drawing is used.
A spring (spring constant = 418 N/m) is attached to the block. Someone pushes on the end of the spring in a direction perpendicular to the wall until the block does not slip downward. If the spring i