Friction
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A 150-lb fireman is holding a hose which has a nozzle diameter of 1 inch and hose diameter of 2 inches.
If the velocity of the water at discharge is 60 ft/s - determine the resultant normal and frictional force acting on the man's feet at the ground. (Neglect the weight of the hose and the water within it. yw = 62.4 lb/ft3).
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Solution Summary
A fireman is holding a hose which has a nozzle (hose and nozzle diameter are given). Given the velocity of the water at discharge, this solution helps determine the resultant normal and frictional force acting on the man's feet at the ground. Step by step solution provided.
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Please refer to the attachment.
As per Newton's second law of motion, rate of change of momentum results in application of a force which is equal to the rate of change of momentum (in magnitude as well as direction). As the water enters the nozzle from the hose, its speed increases resulting in a change of momentum of the water and hence a force. This force is transferred from the hose to the fire man as he is holding it firmly.
Volume of water flowing at any section of the hose per sec = speed of water in the hose x area of ...
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