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    Acceleration, distance, and velocity of Car A and Car B

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    Car A accelerates from rest with 2m/sec^2 and Car B is moving with a constant velocity of 25 m/s. at the instant t=0.

    (a) distance between the two cars at t=5 sec.
    (b) time for the cars to arrive at the same location.
    (c) distance of car A from the origin when they arrive at the same location.
    (d) speed of car A at the instant they arrive at same location.
    (e) acceleration needed for car B to come to a stop over a distance of 100 meters.

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    Solution Preview

    velocity of car A = va = 0 + 2*t = 2t (where t is time)
    velocity of car B = vb = 25 m/s
    sa(t) = ut + (1/2)at^2
    => sa(t) = 0 + (1/2)*2*t^2 = t^2
    sb(t) = ...

    Solution Summary

    The problems are solved with good explanations and detail workings.