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    Simple Acceleration

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    Car A is at rest (0 mi/hr), while car B is going 90m/hr with constant velocity. How fast will car A have to travel from rest in order to catch up to car B over a distance of 3 miles? How long will it take for car A to catch car B?

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    Solution Preview

    Time taken by car B to travel a distance of 3 miles = 3/90 = 1/30 hr

    Now for car A:
    Initial velocity u = 0
    Displacement s = 3 miles
    time t = 1/30 ...

    Solution Summary

    s = u*t + (1/2)*a*t^2