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heat evolved in the reation between HCl and NaOH

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When we add 50.0 mL of 0.250 M HCl to 50.0 mL of 0.250 M NaOH, the temperature increases by 1.71 degrees C and 715 J of heat is evolved by the reaction. Which of the following will be true when we add 100.0 mL of 0.125 M HCl to 100.0 mL of 0.125 M NaOH?

A. The temperature change will be 1.71 C and the heat evolved will be 715 J.
B. The temperature change will be greater than 1.71 C and the heat evolved will be greater than 715 J.
C. The temperature change will be greater than 1.71 C, and the heat evolved will be 715 J.
D. The temperature increases will ne less than 1.71 C, and the heat evolved will be 715 J.
E. The temperature change will be less than 1.71, and the heat evolved will be less than 715 J.

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Solution Summary

It finds the temperature change in the reation between HCl and NaOH.

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In 50.0 mL of 0.250 M HCl, there are 50 * 0.250 = 12.5 mmol HCl.
Also there are 12.5 mmol NaOH in 50.0 mL of 0.250 NaOH
HCl + NaOH = NaCl + H2O.
So both of the reactants are consumed ...

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