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    buoyant force

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    An object falls off of a pier and into the ocean (sea water) where it displaces a total volume of 3.8 cubic meters of sea water. What is the buoyant force acting on the object in newtons? You will need to use the mass density form of the buoyant force equation in order to work the problem in the mks system.

    © BrainMass Inc. brainmass.com December 24, 2021, 10:08 pm ad1c9bdddf
    https://brainmass.com/physics/system-work/buoyant-force-447635

    SOLUTION This solution is FREE courtesy of BrainMass!

    The buoyant force equation
    F = dVg
    where density of sea water d = 1025 kg/m^3

    the volume of sea water displaced V = 3.8 m^3
    and g = 9.8 m/s^2

    so the buoyant force
    F = 1025 * 3.8 * 9.8 = 38171 Newtons

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 10:08 pm ad1c9bdddf>
    https://brainmass.com/physics/system-work/buoyant-force-447635

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