(b) If the star's radius is 605,000 km, what is the total power output of the star?
2 ...... W
According to the Stefan-Boltzmann law, The energy radiated by a blackbody radiator "per second per unit area" is proportional to the fourth power of the absolute temperature.
Energy per area per second = sigma x T^4 Joules/m^2 s
where sigma = 5.67 x 10^-8 W/m^2 ...
Easy to understand step by step solution is provided.