A guy fires a desert eagle chambered for 44 mag at ground level on a flat area of the moon. The projectile exits the muzzle at 1450 fps (442m/s) and at an angle 27 degrees above the ground. Supposing the gravitation on the moon is 1/6 that it is on earth, determine both how far the bullet went and how long it took to get there.
g on moon = 9.8/6 = 1.6333 m/s^2
Time to reach peak:
Vy = 0; Uy = U*Sin x
0 = USin x -gt ...
The solution provides a step by step calculation for projectile motion.