Transmission coefficient of the finite square well
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A particle of positive energy approaches the square well illustrated in fig 3.5 - attached- from the left. some of the wave will be transmitted and some will be reflected.
a) calculate the transmission amplitude
b) show that the transmission amplitude equals 1 when 2k'L = npi, where k'= [sq rt ((2m(E+V_0))/h-bar] is the wavenumber in the region of the well. thus the potential well becomes transparent at a discrete set of energies (Ramsauer effect).
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Solution Summary
The 6-pages solution shows how to obtain the transmission coefficient for the finite symmetric square well when E>0
Solution Preview
Schrodinger equation is valid everywhere.
It is:
(1.1)
We divide space into three regions as shown in the figure below:
In region (1) and (3) the equation is:
(1.2)
Rewriting:
(1.3)
Where
(1.4)
The solution to this harmonic equation is:
(1.5)
And:
(1.6)
However, since in region (3) we do not expect a wave moving to the left, we can already state that
(1.7)
And therefore:
(1.8)
Over the well, the ...
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