"Calculate the moment of inertia of a 14.0 kg sphere of radius 0.645 m when the axis of rotation is through its center."
I thought the equation was simply:
I = mr^2 = (14.0)(0.645)2 = 5.82 kg*m^s
but that's not the answer.© BrainMass Inc. brainmass.com March 4, 2021, 5:46 pm ad1c9bdddf
The moment of inertia of a 14.0 kg sphere of radius 0.625m is examined. The axis of rotation is given.