# Moment of inertia of a 14.0 kg sphere of radius 0.645 m

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"Calculate the moment of inertia of a 14.0 kg sphere of radius 0.645 m when the axis of rotation is through its center."

I thought the equation was simply:

I = mr^2 = (14.0)(0.645)2 = 5.82 kg*m^s

but that's not the answer.

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##### Solution Summary

The moment of inertia of a 14.0 kg sphere of radius 0.625m is examined. The axis of rotation is given.

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