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    Moment of inertia of a 14.0 kg sphere of radius 0.645 m

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    "Calculate the moment of inertia of a 14.0 kg sphere of radius 0.645 m when the axis of rotation is through its center."

    I thought the equation was simply:

    I = mr^2 = (14.0)(0.645)2 = 5.82 kg*m^s

    but that's not the answer.

    © BrainMass Inc. brainmass.com March 4, 2021, 5:46 pm ad1c9bdddf
    https://brainmass.com/physics/rotation/moment-inertia-kg-sphere-radius-10711

    Solution Summary

    The moment of inertia of a 14.0 kg sphere of radius 0.625m is examined. The axis of rotation is given.

    $2.49

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