"A 243 N sphere 0.199 m in radius rolls, without slipping, 6.06 m down a ramp that is inclined at 36.9° with the horizontal. What is the angular speed of the sphere at the bottom of the hill if it starts from rest?"
243 Cos (theta) = m * a
i.e it just starts to roll
you can find a.
Now find the velocity by the formula,
V^2 - U^2 = 2 ...
Solution Summary
"A 243 N sphere 0.199 m in radius rolls, without slipping, 6.06 m down a ramp that is inclined at 36.9° with the horizontal. What is the angular speed of the sphere at the bottom of the hill if it starts from rest?"
