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    solve angular speed based on moment of inertia

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    An ice skater has a moment of inertia of 5.0 kg-m^2 when her arms are outstretched. At this time, she is spinning at 3.0 revolutions per second. If she pulls her arms in, she decreases her moment of inertia to 2.0 kg-m^2. How fast is she spinning then?
    Please provide detailed explanation.

    © BrainMass Inc. brainmass.com December 24, 2021, 10:19 pm ad1c9bdddf
    https://brainmass.com/physics/angular-momentum/solve-angular-speed-based-moment-inertia-462817

    SOLUTION This solution is FREE courtesy of BrainMass!

    In this question, there is a conservation of angular momentum.

    Angular momentum = (Moment of Inertia) x (Angular Speed)

    The initial angular momentum must be equal to the final angular momentum.

    (Mom. of I.)1 x (Ang. Speed)1 = (Mom. of I.)2 x (Ang. Speed)2
    5 kg.m^2 * 3 rps=2 kg.m^2 * w

    Therefore the angular speed of the ice skater (w) = 5x3/2 = 7.5 rps.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 10:19 pm ad1c9bdddf>
    https://brainmass.com/physics/angular-momentum/solve-angular-speed-based-moment-inertia-462817

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