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Uncertainty: Particle in a Box

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A helium atom is confined to a one-dimensional space 8 x 10^-10m.
1. What is the minimum uncertainty in the momentum of the helium atom?
2. What is the minimum velocity of the helium atom?
3. What is the minimum energy of the helium atom?

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Solution Summary

The solution determines the minimum uncertainty in the momentum of the helium atom, the minimum velocity of the helium atom, and the minimum energy of the helium atom.

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L = 8*10^(-10) m
h_cut = h/(2*pi) = 1.054*10^(-34) J.s
h=6.626*10^(-34)J.s
mass of helium atom, m = 4*1.67*10^(-27) kg

1. Minimum uncertainty in momentum (n=1):
delta(p) = ...

Solution provided by:
Amrit Lal Ahuja, PhD (IP)
Education
  • BEng, Allahabad University, India
  • MSc , Pune University, India
  • PhD (IP), Pune University, India
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