A 60.0 ohm resistor is connected in parallel with a 115.0 ohm resistor. This parallel group is connected in series with a 15.0hm resistor. The total combination is connected across a 15.0-V battery. Find the current and power in the 115 ohm resistor.
The total resistance of the network = 15 series + (60 parallel 115)
R = 15 + 60*115/175 = ...
The solution is given in a step-by-step equational process.