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Period of a pendulum - amplitude
53906 Period of a pendulum - amplitude When the amplitude of a pendulum decreases to half its initial value. Will the period have doubled, halved or stayed the same?
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Simple pendulum period depends on length, amplitude, gravity
282521 Simple pendulum period depends on length, amplitude, gravity Consider an ideal pendulum consisting of a "bob" of mass m hanging from a light (massless) string of length L. The pendulum swings back and forth in simple harmonic motion (SHM).
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Mass-spring system, clock pendulum, submarine sonar echo
If the mass is 0.25 kg, the spring constant is 12 N/m, and the amplitude is 15 cm, (a) what is the maximum speed of the mass, and (b) where does this occur? (c) What is the speed at half amplitude position?
2.
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Oscillation of pendulum, inertia, amplitude, wave speed
394779 Oscillation of pendulum, inertia, amplitude, wave speed See attached file for proper format.
6. A physical pendulum consists of a uniform rod of mass M and length L.
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Oscillation and Pendulum Motion
56258 Oscillation and Pendulum Motion A mass on a string of unknown length oscillates as a pendulum with a period of 4.0 (s). Parts a to d are independent questions, each referring to the initial situation. What is the period if:
a.
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simple harmonic motion of spring and simple pendulum
A simple pendulum is suspended from a ceiling of an elevator. The elevator is accelerating upwards with acceleration a. The period of the pendulum, in terms of its length L, g, and a is
20.
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Physics Questions
What is the period of such a pendulum? (B) If the pendulum were oscillating with an amplitude of 3.0 degrees, what would be the total energy of the system? (Hint: what is the maximum change in height of the bob?)
9.
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Perfect spring, spider silk, pendulum, energy of climber
Suppose a pendulum has a period of 4.00 s when swinging on the Earth. (Assume
g = 9.80 m/s2.) What would be the period of the same pendulum if placed on the moon, where g = 1.62 m/s2?
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Pendulum
No of oscillations made by the pendulum in 60000 sec = 60000/4.196 =14299
The problem on pendulum has been solved using the concept of centre of mass and determining the length of an equivalent pendulum and then calculating its time period.