Physics - Optics
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A lens has a focal length f = - 10 cm (the negative focal length indicating that it is a diverging lens). An object is put in front of lens at a distance of 15 cm. Where will the image appear? Calculate the image distance i. Is it a real or virtual image? What is the magnification of the lens? Is the image larger or smaller than the object? Is it upright or inverted?
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The expert examines optics magnification. A complete, neat, and step-by-step solution is provided.
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We have 1/u + 1/v = 1/f
1/15 + 1/v = -1/10
1/v = -1/10 ?1/15 = ...
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