Explore BrainMass
Share

Explore BrainMass

    Question & solution around the trans impedance opamp circuit

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    (a) The circuit of FIGURE 2 (attached) is known as a trans-impedance circuit used for the measurement of very small currents. Derive the relationship between the output voltage V and the input current I; i.e. if V = kI find k in terms of R1, R2 and Rf.

    (b) Calculate the current I if Rf =10 mOhm (milli-Ohms), R1 = 90 kOhm, R2=10 kOhm, and V= 0.1 V.

    © BrainMass Inc. brainmass.com October 10, 2019, 2:13 am ad1c9bdddf
    https://brainmass.com/physics/ohms-law/question-solution-around-the-trans-impedance-opamp-circuit-367567

    Attachments

    Solution Preview

    For the Ideal Op-Amp, the virtual earth theorem applies, meaning that the potential at both the + and - terminals is ~ 0 V. We can thus determine the potential at point A as that due to the potential divider formed by Rf parallel with R2 in turn in series with R1. So

    R2 || Rf = R2*Rf/(R2 + Rf)

    Hence by voltage divider ...

    Solution Summary

    A relationship is derived between the input current and the measured output voltage for the transimpedance Opsamp circuit in terms of the resistances R1, R2 and Rf. Values of R1 = 90 kOhm, R2 = 10 kOhm, Rf = 10 mOhm with Vout = 0.1V and the input current value is derived

    $2.19