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# Working with buoyant force: Stone dropped into sea water

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A stone of density 5g/cm^3 completely immersed in sea water is allowed to sink from rest. Calculate the depth to which the stone would sink in two seconds. Neglect effect of friction. Relative density of sea water = 1.025 and g = 980cm/s^2

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#### Solution Preview

Let m be the mass of the stone,
<br>
<br>Weight of sea water displaced = d v g
<br>where d is the relative density of sea water.
<br>
<br>= 1.025 x (m/5) x g
<br>
<br>This must be equal to the buoyant force in the upward ...

#### Solution Summary

Very detail answer with easy to understand steps. It will enable you to do similar problems yourself.

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